"The population of bacteria doubles every 3 hours." A student writes P = 100(2)^t . Wrong. If it doubles every 3 hours , the exponent must be t/3 . The correct formula is P = 100(2)^(t/3) .
Two classes, Dr. Chiu’s and Ms. Minster’s, both have 23 students. Dr. Chiu’s scores are spread across the 95%–100% range fairly evenly. In Ms. Minster’s class, 16 out of 23 students scored exactly 97%. Which statement is true? A) The standard deviation of Dr. Chiu’s class is higher. hard sat questions math
If there is only one solution, the quadratic must be a perfect square. $x^2 - 12x + k = (x - m)^2$ The middle term is $-12x$, which corresponds to $2mx$. $2m = -12 \Rightarrow m = -6$. Therefore, $(x - 6)^2 = x^2 - 12x + 36$. $k = 36$. "The population of bacteria doubles every 3 hours
Which of the following correctly orders the standard deviations (\sigma_A, \sigma_B, \sigma_C)? The correct formula is P = 100(2)^(t/3)
"The population of bacteria doubles every 3 hours." A student writes P = 100(2)^t . Wrong. If it doubles every 3 hours , the exponent must be t/3 . The correct formula is P = 100(2)^(t/3) .
Two classes, Dr. Chiu’s and Ms. Minster’s, both have 23 students. Dr. Chiu’s scores are spread across the 95%–100% range fairly evenly. In Ms. Minster’s class, 16 out of 23 students scored exactly 97%. Which statement is true? A) The standard deviation of Dr. Chiu’s class is higher.
If there is only one solution, the quadratic must be a perfect square. $x^2 - 12x + k = (x - m)^2$ The middle term is $-12x$, which corresponds to $2mx$. $2m = -12 \Rightarrow m = -6$. Therefore, $(x - 6)^2 = x^2 - 12x + 36$. $k = 36$.
Which of the following correctly orders the standard deviations (\sigma_A, \sigma_B, \sigma_C)?